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Sphere Volume Word Problems: 5 Real-World Scenarios Solved

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Formula: V = ⁴⁄₃ × π × r³
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Problem 1: Basketball Air Capacity

Scenario: A regulation basketball has a circumference of 75 cm. How many cubic centimeters of air does it hold?

  1. Find radius: = C / (2\pi) = 75 / (2 imes 3.14159) \approx 11.9366 ext{ cm}$.
  2. Calculate volume: = ⁴⁄₃ imes \pi imes (11.9366)^3 \approx ⁴⁄₃ imes \pi imes 1700.74 \approx \mathbf{7,124.7 ext{ cm}^3}$.

Problem 2: Melting Spherical Ice Ball

Scenario: A cocktail ice ball has diameter 6 cm. If it melts into a cylindrical glass of diameter 8 cm, what will the liquid water height be?

  • Ice volume: = ¹⁄₆\pi(6)^3 = 36\pi ext{ cm}^3 \approx 113.10 ext{ cm}^3$.
  • Glass base area: = \pi(d/2)^2 = \pi(4)^2 = 16\pi ext{ cm}^2$.
  • Water height: = V / A = (36\pi) / (16\pi) = 36/16 = \mathbf{2.25 ext{ cm}}$.

Common Questions About Sphere Volume Word Problems: 5 Real-World Scenarios Solved

First solve for radius using r = C / 2π, then substitute r into V = (4/3)πr³.

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